Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:19Z
∇²n = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
273K
∫₀^∞ e^(-z²) dz = √π / 2
263K
9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{12}{6} \sum_{i=1}^{n} i^{2}
333K
11γ² + 3γ + 6 = 0
\frac{4}{6} \sum_{i=1}^{n} i^{2}
297K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
404K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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