Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:39Z

11n² + 5n + 4 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

ΔS ≥ 0

186K

8ψ² + 7ψ + 0 = 0

411K

4φ² + 6φ + 2 = 0

d/dt [t^3] = 3t^2

448K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

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∫₀^∞ e^(-φ²) dφ = √π / 2

∇ × E = −∂B/∂t

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∫₀^∞ e^(-t²) dt = √π / 2

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

80K

det| 11 5 ; 0 12 | = 132

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