Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:38Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 4 7 ; 2 5 | = 6

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

448K

PV = nRT

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

459K

d/dφ [φ^1] = 1φ^0

406K

det| 9 4 ; 1 10 | = 86

181K

11φ² + 4φ + 0 = 0

80K

F = G m₁m₂ / r²

359K