Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:43Z

∇²t = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 6 4 ; 3 7 | = 30

∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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ΔS ≥ 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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8ψ² + 7ψ + 0 = 0

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1z² + 3z + 2 = 0

iħ ∂ψ/∂t = Ĥψ

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2n² + 4n + 0 = 0

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7t² + 3t + 1 = 0

10ψ² + 5ψ + 0 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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