Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:04Z

∑_{k=1}^{n} k = n(n+1)/2

E = mc²

451K

∇ × E = −∂B/∂t

264K

det| 8 9 ; 3 9 | = 45

iħ ∂ψ/∂t = Ĥψ

297K

det| 11 4 ; 5 12 | = 112

252K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

PV = nRT

48K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

411K

det| 2 3 ; 3 3 | = -3

8ψ² + 7ψ + 0 = 0

377K

11z² + 3z + 4 = 0

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d/dt [t^3] = 3t^2

401K