Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:49Z

det| 5 4 ; 6 6 | = 6

det| 7 4 ; 4 8 | = 40

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N₂ + 3H₂ ⇌ 2NH₃

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∇²φ = 0

∑_{k=1}^{n} k = n(n+1)/2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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det| 12 5 ; 4 13 | = 136

det| 3 7 ; 2 4 | = -2

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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∑_{k=1}^{n} k = n(n+1)/2

e^{i\pi} + 1 = 0

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N₂ + 3H₂ ⇌ 2NH₃

406K