Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:30Z

11n² + 5n + 4 = 0

∫₀^∞ e^(-t²) dt = √π / 2

460K

CH₄ + 2O₂ → CO₂ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

F = G m₁m₂ / r²

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

7r² + 8r + 5 = 0

459K

∇²ω = 0

406K

∇²ω = 0

∇ × E = −∂B/∂t

181K

11t² + 9t + 7 = 0

80K

d/dr [r^2] = 2r^1

CH₄ + 2O₂ → CO₂ + 2H₂O

359K

ΔS ≥ 0