Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 01:37Z

11φ² + 9φ + 3 = 0

2H₂ + O₂ → 2H₂O

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F = G m₁m₂ / r²

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∫₀^∞ e^(-y²) dy = √π / 2

det| 7 4 ; 4 8 | = 40

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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\lim_{y\to 0} \frac{\sin y}{y} = 1

e^{i\pi} + 1 = 0

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∇ × E = −∂B/∂t

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇²θ = 0

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