Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:26Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

PV = nRT

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

∇²t = 0

411K

4φ² + 6φ + 2 = 0

det| 12 6 ; 0 13 | = 156

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

459K

\lim_{t\to 0} \frac{\sin t}{t} = 1

406K

∇²ω = 0

d/dt [t^3] = 3t^2

181K

det| 7 2 ; 7 8 | = 42

80K

det| 9 4 ; 1 10 | = 86

359K

F = G m₁m₂ / r²

455K