Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:29Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇ × E = −∂B/∂t

186K

8ψ² + 7ψ + 0 = 0

411K

4φ² + 6φ + 2 = 0

F = G m₁m₂ / r²

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 10 2 ; 3 11 | = 104

459K

CaCO₃ → CaO + CO₂

406K

∂α/∂ω = 3α

181K

d/dt [t^3] = 3t^2

80K