Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z

N₂ + 3H₂ ⇌ 2NH₃

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\frac{8}{7} \sum_{i=1}^{n} i^{2}

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9ψ² + 4ψ + 2 = 0

\frac{12}{6} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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d/dβ [β^6] = 6β^5

∂γ/∂z = 6γ

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N₂ + 3H₂ ⇌ 2NH₃

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det| 6 1 ; 4 7 | = 38

det| 7 4 ; 4 8 | = 40

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λ = h/p

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7r² + 8r + 5 = 0

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