Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:10Z

N₂ + 3H₂ ⇌ 2NH₃

10β² + 4β + 1 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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9ψ² + 4ψ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∇²ω = 0

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d/dβ [β^6] = 6β^5

F = G m₁m₂ / r²

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 6 1 ; 4 7 | = 38

∇ × E = −∂B/∂t

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∫₀^∞ e^(-θ²) dθ = √π / 2

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det| 3 7 ; 2 4 | = -2

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det| 7 8 ; 4 8 | = 24

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det| 7 4 ; 4 8 | = 40

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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