Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:51Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

∇ × E = −∂B/∂t

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∇²θ = 0

264K

\frac{8}{4} \sum_{i=1}^{n} i^{2}

∇²r = 0

297K

1θ² + 2θ + 6 = 0

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N₂ + 3H₂ ⇌ 2NH₃

e^{i\pi} + 1 = 0

48K

8ψ² + 7ψ + 0 = 0

411K

2α² + 3α + 3 = 0

d/dt [t^3] = 3t^2

377K

12y² + 5y + 7 = 0

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det| 10 7 ; 6 11 | = 68

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

401K

∑_{k=1}^{n} k = n(n+1)/2

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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