Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 01:37Z

11φ² + 9φ + 3 = 0

E = mc²

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-y²) dy = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 7 2 ; 7 8 | = 42

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\lim_{y\to 0} \frac{\sin y}{y} = 1

8ψ² + 7ψ + 0 = 0

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6x² + 6x + 1 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇²β = 0

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N₂ + 3H₂ ⇌ 2NH₃

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iħ ∂ψ/∂t = Ĥψ

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