Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:50Z

∇²n = 0

∇ × E = −∂B/∂t

273K

E = mc²

263K

9r² + 4r + 1 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

139K

iħ ∂ψ/∂t = Ĥψ

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

333K

d/dt [t^3] = 3t^2

160K

11γ² + 3γ + 6 = 0

10ψ² + 5ψ + 0 = 0

439K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

8ψ² + 7ψ + 0 = 0

297K

PV = nRT

128K

det| 6 1 ; 3 7 | = 39