Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:49Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

\frac{4}{6} \sum_{i=1}^{n} i^{2}

186K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

411K

4φ² + 6φ + 2 = 0

\frac{2}{2} \sum_{i=1}^{n} i^{2}

448K

d/dt [t^3] = 3t^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∫₀^∞ e^(-x²) dx = √π / 2

459K

11t² + 9t + 7 = 0

406K

∇²ω = 0

8ψ² + 7ψ + 0 = 0

181K

det| 5 9 ; 7 6 | = -33

80K

d/dr [r^2] = 2r^1