Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:18Z

∇²n = 0

10ψ² + 5ψ + 0 = 0

273K

∑_{k=1}^{n} k = n(n+1)/2

263K

9r² + 4r + 1 = 0

d/dx [x^3] = 3x^2

139K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 9 4 ; 1 10 | = 86

333K

d/dt [t^3] = 3t^2

160K

11γ² + 3γ + 6 = 0

det| 5 3 ; 7 6 | = 9

439K

∇²t = 0

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

∑_{k=1}^{n} k = n(n+1)/2

297K