Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:27Z

CH₄ + 2O₂ → CO₂ + 2H₂O

E = mc²

460K

8ψ² + 7ψ + 0 = 0

438K

det| 1 1 ; 4 2 | = -2

∇²n = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

CaCO₃ → CaO + CO₂

∑_{k=1}^{n} k = n(n+1)/2

448K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

22K

det| 8 4 ; 2 9 | = 64

det| 2 8 ; 7 3 | = -50

459K

∇ × E = −∂B/∂t

406K

4n² + 8n + 6 = 0

d/dx [x^3] = 3x^2

181K

d/dt [t^3] = 3t^2

80K

6α² + 1α + 5 = 0

iħ ∂ψ/∂t = Ĥψ

359K

\oint_C \vec{F}\cdot d\vec{r} = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

∫₀^∞ e^(-ω²) dω = √π / 2