Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:04Z

11n² + 5n + 4 = 0

PV = nRT

460K

det| 9 4 ; 1 10 | = 86

438K

∫₀^∞ e^(-x²) dx = √π / 2

11t² + 9t + 7 = 0

186K

∫₀^∞ e^(-x²) dx = √π / 2

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

det| 3 1 ; 7 4 | = 5

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

PV = nRT

406K

d/dt [t^3] = 3t^2

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

80K

F = G m₁m₂ / r²

359K

∑_{k=1}^{n} k = n(n+1)/2

455K