Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:48Z

11n² + 5n + 4 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

460K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

438K

∫₀^∞ e^(-x²) dx = √π / 2

iħ ∂ψ/∂t = Ĥψ

186K

F = G m₁m₂ / r²

411K

4φ² + 6φ + 2 = 0

∇ × E = −∂B/∂t

448K

det| 9 5 ; 1 10 | = 85

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∫₀^∞ e^(-φ²) dφ = √π / 2

PV = nRT

459K

det| 7 4 ; 4 8 | = 40

406K

∇²ω = 0

8θ² + 8θ + 6 = 0

181K