Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:03Z

10y² + 2y + 6 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

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F = G m₁m₂ / r²

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∫₀^∞ e^(-t²) dt = √π / 2

8θ² + 8θ + 6 = 0

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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e^{i\pi} + 1 = 0

e^{i\pi} + 1 = 0

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det| 7 4 ; 4 8 | = 40

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∇ × E = −∂B/∂t

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∂ψ/∂β = 3ψ

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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