Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:19Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

e^{i\pi} + 1 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

λ = h/p

186K

det| 4 8 ; 3 5 | = -4

411K

4φ² + 6φ + 2 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

448K

E = mc²

22K

∑_{k=1}^{n} k = n(n+1)/2

459K

d/dt [t^3] = 3t^2

406K

9α² + 7α + 5 = 0

181K

det| 2 6 ; 0 3 | = 6

80K

det| 9 4 ; 1 10 | = 86

359K

det| 3 7 ; 2 4 | = -2

455K