Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:33Z
det| 6 5 ; 4 7 | = 22
∑_{k=1}^{n} k = n(n+1)/2
460K
∇²φ = 0
det| 4 2 ; 6 5 | = 8
186K
\frac{9}{2} \sum_{i=1}^{n} i^{2}
F = ma
det| 5 3 ; 7 6 | = 9
459K
∑_{k=1}^{n} k = n(n+1)/2
406K
ΔS ≥ 0
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃