Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 02:14Z
\frac{4}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
263K
∂y/∂t = 6y
\frac{12}{1} \sum_{i=1}^{n} i^{2}
det| 1 4 ; 3 2 | = -10
333K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{12}{6} \sum_{i=1}^{n} i^{2}
413K
2H₂ + O₂ → 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2