Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:33Z

∑_{k=1}^{n} k = n(n+1)/2

det| 7 8 ; 4 8 | = 24

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∫₀^∞ e^(-z²) dz = √π / 2

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det| 8 9 ; 3 9 | = 45

det| 7 4 ; 4 8 | = 40

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∑_{k=1}^{n} k = n(n+1)/2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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11t² + 9t + 5 = 0

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det| 2 3 ; 3 3 | = -3

7y² + 9y + 1 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇²θ = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∑_{k=1}^{n} k = n(n+1)/2

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