Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 05:47Z

λ = h/p

det| 9 8 ; 3 10 | = 66

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 3 9 ; 5 4 | = -33

6r² + 3r + 1 = 0

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d/dt [t^3] = 3t^2

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iħ ∂ψ/∂t = Ĥψ

1θ² + 2θ + 6 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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det| 8 7 ; 0 9 | = 72

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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∇ × E = −∂B/∂t

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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8ψ² + 7ψ + 0 = 0

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