Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:50Z

∇²n = 0

∇²z = 0

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∑_{k=1}^{n} k = n(n+1)/2

263K

9r² + 4r + 1 = 0

det| 11 5 ; 0 12 | = 132

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det| 11 9 ; 0 12 | = 132

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

8ψ² + 7ψ + 0 = 0

333K

6n² + 7n + 6 = 0

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11γ² + 3γ + 6 = 0

iħ ∂ψ/∂t = Ĥψ

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

413K

E = mc²

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det| 10 2 ; 3 11 | = 104

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N₂ + 3H₂ ⇌ 2NH₃

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