Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

\lim_{r\to 0} \frac{\sin r}{r} = 1

438K

∫₀^∞ e^(-x²) dx = √π / 2

∂y/∂n = 5y

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

CaCO₃ → CaO + CO₂

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

10t² + 9t + 5 = 0

181K

det| 7 4 ; 4 8 | = 40

80K

det| 8 9 ; 4 9 | = 36

359K