Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:11Z

det| 11 2 ; 2 12 | = 128

∇ × E = −∂B/∂t

460K

8ψ² + 7ψ + 0 = 0

438K

CaCO₃ → CaO + CO₂

11z² + 3z + 4 = 0

186K

d/dt [t^3] = 3t^2

411K

3θ² + 7θ + 1 = 0

∇²θ = 0

448K

det| 10 2 ; 3 11 | = 104

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

8θ² + 8θ + 6 = 0

459K

9θ² + 7θ + 4 = 0

406K

2H₂ + O₂ → 2H₂O

∇ × E = −∂B/∂t

∫₀^∞ e^(-z²) dz = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

10γ² + 5γ + 7 = 0

1ω² + 1ω + 3 = 0