Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:09Z

10y² + 2y + 6 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-t²) dt = √π / 2

6r² + 3r + 1 = 0

186K

d/dt [t^3] = 3t^2

411K

e^{i\pi} + 1 = 0

CaCO₃ → CaO + CO₂

448K

∇²ω = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{r\to 0} \frac{\sin r}{r} = 1

459K

5z² + 8z + 3 = 0

406K

∇ × E = −∂B/∂t

181K

∂z/∂φ = 7z

80K

8ψ² + 7ψ + 0 = 0

359K