Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 13:46Z

F = ma

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

273K

iħ ∂ψ/∂t = Ĥψ

263K

\lim_{β\to 0} \frac{\sin β}{β} = 1

E = mc²

139K

d/dt [t^3] = 3t^2

108K

N₂ + 3H₂ ⇌ 2NH₃

8ψ² + 7ψ + 0 = 0

333K

PV = nRT

160K

e^{i\pi} + 1 = 0

11φ² + 4φ + 0 = 0

439K

∇ × E = −∂B/∂t

413K

1r² + 8r + 1 = 0

PV = nRT

297K

\oint_C \vec{F}\cdot d\vec{r} = 0

128K

e^{i\pi} + 1 = 0

det| 9 8 ; 3 10 | = 66

404K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

58K

iħ ∂ψ/∂t = Ĥψ