Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:43Z
10y² + 2y + 6 = 0
∫₀^∞ e^(-t²) dt = √π / 2
e^{i\pi} + 1 = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
22K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 3 6 ; 0 4 | = 12
459K
det| 9 4 ; 1 10 | = 86
406K
λ = h/p
iħ ∂ψ/∂t = Ĥψ