Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 16:26Z
∂ψ/∂φ = 6ψ
∑_{k=1}^{n} k = n(n+1)/2
451K
11ψ² + 2ψ + 6 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
297K
∑_{k=1}^{n} k = n(n+1)/2
252K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
48K
det| 7 4 ; 4 8 | = 40
411K
\frac{9}{7} \sum_{i=1}^{n} i^{2}
\lim_{t\to 0} \frac{\sin t}{t} = 1
377K
\frac{2}{8} \sum_{i=1}^{n} i^{2}
8y² + 6y + 2 = 0
\frac{10}{3} \sum_{i=1}^{n} i^{2}