Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:36Z

det| 11 2 ; 2 12 | = 128

∇ × E = −∂B/∂t

460K

det| 10 2 ; 3 11 | = 104

438K

CaCO₃ → CaO + CO₂

8ψ² + 7ψ + 0 = 0

186K

iħ ∂ψ/∂t = Ĥψ

411K

3θ² + 7θ + 1 = 0

∂n/∂θ = 3n

448K

d/dt [t^3] = 3t^2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 3 7 ; 2 4 | = -2

459K

\lim_{t\to 0} \frac{\sin t}{t} = 1

406K

2H₂ + O₂ → 2H₂O

10ω² + 7ω + 4 = 0

181K

∇ × E = −∂B/∂t

∫₀^∞ e^(-z²) dz = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

10γ² + 5γ + 7 = 0