Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:49Z

11n² + 5n + 4 = 0

λ = h/p

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

∫₀^∞ e^(-θ²) dθ = √π / 2

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

det| 9 4 ; 1 10 | = 86

448K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

iħ ∂ψ/∂t = Ĥψ

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²ω = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

181K

F = G m₁m₂ / r²

80K

d/dr [r^2] = 2r^1

12n² + 2n + 2 = 0

359K

ΔS ≥ 0

8β² + 5β + 0 = 0

det| 12 6 ; 6 13 | = 120