Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:07Z
10y² + 2y + 6 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∫₀^∞ e^(-z²) dz = √π / 2
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∫₀^∞ e^(-t²) dt = √π / 2
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{r\to 0} \frac{\sin r}{r} = 1
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 3 7 ; 2 4 | = -2
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\frac{2}{2} \sum_{i=1}^{n} i^{2}
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