Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:32Z

∇²t = 0

det| 7 9 ; 1 8 | = 47

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CH₄ + 2O₂ → CO₂ + 2H₂O

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det| 6 4 ; 3 7 | = 30

∇²t = 0

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det| 7 4 ; 4 8 | = 40

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ΔS ≥ 0

F = G m₁m₂ / r²

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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1z² + 3z + 2 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

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CH₄ + 2O₂ → CO₂ + 2H₂O

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6r² + 3r + 1 = 0

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∇ × E = −∂B/∂t

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