Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:36Z

det| 6 5 ; 4 7 | = 22

∇ × E = −∂B/∂t

460K

iħ ∂ψ/∂t = Ĥψ

438K

∇²φ = 0

∑_{k=1}^{n} k = n(n+1)/2

186K

d/dt [t^3] = 3t^2

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

\lim_{t\to 0} \frac{\sin t}{t} = 1

448K

det| 9 4 ; 1 10 | = 86

22K

F = ma

iħ ∂ψ/∂t = Ĥψ

459K

e^{i\pi} + 1 = 0

406K

ΔS ≥ 0

AgNO₃ + NaCl → AgCl↓ + NaNO₃

∇²γ = 0

1φ² + 4φ + 5 = 0