Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:52Z

3γ² + 8γ + 4 = 0

det| 5 6 ; 2 6 | = 18

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

PV = nRT

∑_{k=1}^{n} k = n(n+1)/2

186K

d/dt [t^3] = 3t^2

411K

det| 1 9 ; 5 2 | = -43

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

E = mc²

22K

ω = 2πf

∇²ω = 0

459K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

406K

∇ × E = −∂B/∂t

181K

e^{i\pi} + 1 = 0

80K

8ψ² + 7ψ + 0 = 0

359K