Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:04Z

10y² + 2y + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-t²) dt = √π / 2

∇ × E = −∂B/∂t

186K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

e^{i\pi} + 1 = 0

∇²t = 0

448K

d/dt [t^3] = 3t^2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 9 4 ; 1 10 | = 86

459K

∂ψ/∂β = 3ψ

406K

\lim_{t\to 0} \frac{\sin t}{t} = 1

181K

det| 4 8 ; 3 5 | = -4

80K