Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 03:10Z

∇²x = 0

∑_{k=1}^{n} k = n(n+1)/2

451K

N₂ + 3H₂ ⇌ 2NH₃

264K

det| 3 9 ; 1 4 | = 3

11z² + 3z + 4 = 0

297K

∂γ/∂z = 6γ

252K

CaCO₃ → CaO + CO₂

det| 7 4 ; 4 8 | = 40

48K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

det| 8 9 ; 4 9 | = 36

\lim_{t\to 0} \frac{\sin t}{t} = 1

377K

∑_{k=1}^{n} k = n(n+1)/2

299K

N₂ + 3H₂ ⇌ 2NH₃

401K

11φ² + 4φ + 0 = 0

420K