Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:46Z
10y² + 2y + 6 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
460K
∫₀^∞ e^(-z²) dz = √π / 2
438K
∫₀^∞ e^(-t²) dt = √π / 2
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
448K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 11 5 ; 0 12 | = 132
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∫₀^∞ e^(-α²) dα = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
455K