Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:39Z

∑_{k=1}^{n} k = n(n+1)/2

∇ × E = −∂B/∂t

273K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

263K

e^{i\pi} + 1 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

139K

d/dt [t^3] = 3t^2

108K

2H₂ + O₂ → 2H₂O

F = ma

333K

8ψ² + 7ψ + 0 = 0

160K

det| 4 8 ; 0 5 | = 20

det| 3 7 ; 2 4 | = -2

439K

∇²γ = 0

413K

det| 4 7 ; 7 5 | = -29

det| 2 3 ; 5 3 | = -9

10t² + 5t + 2 = 0

det| 1 6 ; 5 2 | = -28