Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:30Z

e^{i\pi} + 1 = 0

det| 7 4 ; 4 8 | = 40

460K

∇ × E = −∂B/∂t

438K

F = ma

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

411K

12θ² + 8θ + 3 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

ω = 2πf

∇²θ = 0

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

N₂ + 3H₂ ⇌ 2NH₃

F = G m₁m₂ / r²

181K

∇²x = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

E = mc²