Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:32Z

∇²t = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

det| 6 4 ; 3 7 | = 30

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

det| 7 2 ; 7 8 | = 42

411K

ΔS ≥ 0

F = G m₁m₂ / r²

448K

9α² + 7α + 5 = 0

22K

iħ ∂ψ/∂t = Ĥψ

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

∑_{k=1}^{n} k = n(n+1)/2

181K

∇ × E = −∂B/∂t

80K

det| 7 4 ; 4 8 | = 40

359K