Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:50Z

det| 5 4 ; 6 6 | = 6

6t² + 6t + 4 = 0

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∇²β = 0

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∇²φ = 0

∑_{k=1}^{n} k = n(n+1)/2

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det| 9 4 ; 1 10 | = 86

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det| 12 5 ; 4 13 | = 136

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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d/dt [t^3] = 3t^2

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∑_{k=1}^{n} k = n(n+1)/2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∂y/∂n = 5y

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10t² + 9t + 5 = 0

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