Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 02:49Z
det| 5 4 ; 6 6 | = 6
∑_{k=1}^{n} k = n(n+1)/2
460K
det| 9 4 ; 1 10 | = 86
438K
∇²φ = 0
∫₀^∞ e^(-x²) dx = √π / 2
411K
det| 12 5 ; 4 13 | = 136
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
406K
CaCO₃ → CaO + CO₂
E = mc²
ω = 2πf