Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:41Z

CH₄ + 2O₂ → CO₂ + 2H₂O

N₂ + 3H₂ ⇌ 2NH₃

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

det| 1 1 ; 4 2 | = -2

d/dt [t^3] = 3t^2

186K

7γ² + 8γ + 3 = 0

411K

CaCO₃ → CaO + CO₂

F = G m₁m₂ / r²

448K

det| 9 4 ; 1 10 | = 86

22K

det| 8 4 ; 2 9 | = 64

∑_{k=1}^{n} k = n(n+1)/2

459K

\lim_{t\to 0} \frac{\sin t}{t} = 1

406K

4n² + 8n + 6 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

181K

∂α/∂ω = 3α

80K

6α² + 1α + 5 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

∫₀^∞ e^(-ω²) dω = √π / 2