Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:19Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

8ψ² + 7ψ + 0 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

iħ ∂ψ/∂t = Ĥψ

186K

\lim_{t\to 0} \frac{\sin t}{t} = 1

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

F = G m₁m₂ / r²

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

d/dx [x^9] = 9x^8

406K

∑_{k=1}^{n} k = n(n+1)/2

181K

11φ² + 4φ + 0 = 0

80K

d/dt [t^3] = 3t^2

359K

6x² + 6x + 1 = 0

455K