Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:12Z

∇²n = 0

e^{i\pi} + 1 = 0

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8ψ² + 7ψ + 0 = 0

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9r² + 4r + 1 = 0

∇ × E = −∂B/∂t

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3z² + 5z + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dt [t^3] = 3t^2

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11z² + 3z + 4 = 0

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4t² + 3t + 3 = 0

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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det| 10 2 ; 3 11 | = 104

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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